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100-9a^2=0
a = -9; b = 0; c = +100;
Δ = b2-4ac
Δ = 02-4·(-9)·100
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*-9}=\frac{-60}{-18} =3+1/3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*-9}=\frac{60}{-18} =-3+1/3 $
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